Optimal. Leaf size=70 \[ -\frac{B \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{a^{3/2}}-\frac{2 A \sqrt{a+b x^2}}{a^2 x}+\frac{A+B x}{a x \sqrt{a+b x^2}} \]
[Out]
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Rubi [A] time = 0.212819, antiderivative size = 70, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25 \[ -\frac{B \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{a^{3/2}}-\frac{2 A \sqrt{a+b x^2}}{a^2 x}+\frac{A+B x}{a x \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x)/(x^2*(a + b*x^2)^(3/2)),x]
[Out]
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Rubi in Sympy [A] time = 20.0147, size = 60, normalized size = 0.86 \[ - \frac{2 A \sqrt{a + b x^{2}}}{a^{2} x} - \frac{B \operatorname{atanh}{\left (\frac{\sqrt{a + b x^{2}}}{\sqrt{a}} \right )}}{a^{\frac{3}{2}}} + \frac{A + B x}{a x \sqrt{a + b x^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)/x**2/(b*x**2+a)**(3/2),x)
[Out]
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Mathematica [A] time = 0.161076, size = 73, normalized size = 1.04 \[ \frac{\frac{-a A+a B x-2 A b x^2}{x \sqrt{a+b x^2}}-\sqrt{a} B \log \left (\sqrt{a} \sqrt{a+b x^2}+a\right )+\sqrt{a} B \log (x)}{a^2} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x)/(x^2*(a + b*x^2)^(3/2)),x]
[Out]
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Maple [A] time = 0.013, size = 80, normalized size = 1.1 \[ -{\frac{A}{ax}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-2\,{\frac{Axb}{{a}^{2}\sqrt{b{x}^{2}+a}}}+{\frac{B}{a}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-{B\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)/x^2/(b*x^2+a)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x^2 + a)^(3/2)*x^2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.26437, size = 1, normalized size = 0.01 \[ \left [-\frac{2 \,{\left (2 \, A b x^{2} - B a x + A a\right )} \sqrt{b x^{2} + a} \sqrt{a} -{\left (B a b x^{3} + B a^{2} x\right )} \log \left (-\frac{{\left (b x^{2} + 2 \, a\right )} \sqrt{a} - 2 \, \sqrt{b x^{2} + a} a}{x^{2}}\right )}{2 \,{\left (a^{2} b x^{3} + a^{3} x\right )} \sqrt{a}}, -\frac{{\left (2 \, A b x^{2} - B a x + A a\right )} \sqrt{b x^{2} + a} \sqrt{-a} +{\left (B a b x^{3} + B a^{2} x\right )} \arctan \left (\frac{\sqrt{-a}}{\sqrt{b x^{2} + a}}\right )}{{\left (a^{2} b x^{3} + a^{3} x\right )} \sqrt{-a}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x^2 + a)^(3/2)*x^2),x, algorithm="fricas")
[Out]
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Sympy [A] time = 9.37371, size = 235, normalized size = 3.36 \[ A \left (- \frac{1}{a \sqrt{b} x^{2} \sqrt{\frac{a}{b x^{2}} + 1}} - \frac{2 \sqrt{b}}{a^{2} \sqrt{\frac{a}{b x^{2}} + 1}}\right ) + B \left (\frac{2 a^{3} \sqrt{1 + \frac{b x^{2}}{a}}}{2 a^{\frac{9}{2}} + 2 a^{\frac{7}{2}} b x^{2}} + \frac{a^{3} \log{\left (\frac{b x^{2}}{a} \right )}}{2 a^{\frac{9}{2}} + 2 a^{\frac{7}{2}} b x^{2}} - \frac{2 a^{3} \log{\left (\sqrt{1 + \frac{b x^{2}}{a}} + 1 \right )}}{2 a^{\frac{9}{2}} + 2 a^{\frac{7}{2}} b x^{2}} + \frac{a^{2} b x^{2} \log{\left (\frac{b x^{2}}{a} \right )}}{2 a^{\frac{9}{2}} + 2 a^{\frac{7}{2}} b x^{2}} - \frac{2 a^{2} b x^{2} \log{\left (\sqrt{1 + \frac{b x^{2}}{a}} + 1 \right )}}{2 a^{\frac{9}{2}} + 2 a^{\frac{7}{2}} b x^{2}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)/x**2/(b*x**2+a)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.222788, size = 130, normalized size = 1.86 \[ -\frac{\frac{A b x}{a^{2}} - \frac{B}{a}}{\sqrt{b x^{2} + a}} + \frac{2 \, B \arctan \left (-\frac{\sqrt{b} x - \sqrt{b x^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a} a} + \frac{2 \, A \sqrt{b}}{{\left ({\left (\sqrt{b} x - \sqrt{b x^{2} + a}\right )}^{2} - a\right )} a} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x^2 + a)^(3/2)*x^2),x, algorithm="giac")
[Out]